NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry | Monster Thinks

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry

NCERT Solutions for Class 10 Maths are solved by experts of MonsterThinks.in order to help students to obtain excellent marks in their board examination. All the questions and answers in the CBSE NCERT Books have been included on this page. We have provided all the Class 10 Maths NCERT Solutions with a detailed explanation i.e., we have solved all the questions with step-by-step solutions in understandable language. So students having excellent knowledge of NCERT Solutions Class 10 Maths can easily make a grade in their board exams. Read on to find out more about  NCERT Solutions for Class 10 Mathematics.

NCERT Solutions for Class 10 Maths

On this page, each and every question originate with a step-wise solution. Working on NCERT Solutions for Class 10 will help students to get an idea about how to solve problems. With the help of these NCERT Solutions for Class 10 Maths, you can easily grasp basic concepts better and faster. Moreover, it is a perfect guide to help you to score good marks in the CBSE board examination. Just click on the chapter-wise links given below to practice the NCERT Solutions for the respective chapter.

• Chapter 1 Real Numbers
• Chapter 2 Polynomials
• Chapter 3 Pair of Linear Equations in Two Variables
• Chapter 4 Quadratic Equations
• Chapter 5 Arithmetic Progressions
• Chapter 6 Triangles
• Chapter 7 Coordinate Geometry
• Chapter 8 Introduction to Trigonometry
• Chapter 9 Applications of Trigonometry
• Chapter 10 Circle
• Chapter 11 Constructions
• Chapter 12 Areas related to Circles
• Chapter 13 Surface Areas and Volumes
• Chapter 14 Statistics
• Chapter 15 Probability

With the aim of imbibing skills and hard work among the students, the 10th class maths NCERT solutions have been designed. It contains previous years’ questions and answers except those not included in the CBSE 10 maths syllabus.

CBSE NCERT solutions for class 10 maths will help the students acquire good practice to do their CBSE Class 10th exam confidently

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry

Coordinate Geometry Class 10  has four exercises consisting of 33 Problems. The Questions related to finding the distance between two points using their coordinates, the Area of the Triangle, and the Line divided in Ratio (Section Formula) are essential models in class 10 boards.

• Class 10 Maths Coordinate Geometry Ex 7.1
• Class 10 Maths Coordinate Geometry Ex 7.2
• Class 10 Maths Coordinate Geometry Ex 7.3
• Class 10 Maths Coordinate Geometry Ex 7.4

CBSE Class 10 Maths Chapter 7 Coordinate Geometry

• The position of a point P in the Cartesian plane with respect to coordinate axes is represented by the ordered pair (x, y).
  
• The line X’OX is called the X-axis and YOY’ is called the Y-axis.
• The part of the intersection of the X-axis and Y-axis is called the origin O and the coordinates of O are (0, 0).
• The perpendicular distance of a point P from the Y-axis is the ‘x’ coordinate and is called the abscissa.
• The perpendicular distance of a point P from the X-axis is the ‘y’ coordinate and is called the ordinate.
• Signs of abscissa and ordinate in different quadrants are as given in the diagram:
  
• Any point on the X-axis is of the form (x, 0).
• Any point on the Y-axis is of the form (0, y).
• The distance between two points P(x1, y1) and Q (x2, y2) is given by
  PQ = (x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
  Note. If O is the origin, the distance of a point P(x, y) from the origin O(0, 0) is given by
  OP = x2+y2−−−−−−√

Section formula. The coordinates of the point which divides the line segment joining the points A(x1, y1) and B(x2, y2) internally in the ratio m : n are:

The above formula is a section formula. The ratio m: n can also be written as mn : 1 or k : 1, The
co-ordinates of P can also be written as P(x,y) = kx2+x1k+1,ky2+y1k+1

The mid-point of the line segment joining the points P(x1, y1) and Q(x2, y2) is

Here m : n = 1 :1.

Area of a Triangle. The area of a triangle formed by points A(x1 y1), B(x2, y2) and C(x3, y3) is given by | ∆ |,
where ∆ = 12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
where ∆ represents the absolute value.

• Three points are collinear if |A| = 0.
• If P is the centroid of a triangle then the median divides it in the ratio 2 :1. Co-ordinates of P are given by
  P=(x1+x2+x33,y1+y2+y33)

Area of a quadrilateral, ABCD = ar(∆ABC) + ar(∆ADC)