NCERT Solutions For Class 10 Maths Chapter 6 Ex 6.3 | Monster Thinks - Monster Thinks

# NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.3

Get Free NCERT Solutions for Class 10 Maths Chapter 6 Ex 6.3Triangles Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 6.3 Class 10 Maths NCERT Solutions were prepared by Experienced Garry Academy Teachers. Detailed answers to all the questions in Chapter 6 Maths Class 10 Triangles Exercise 6.3 are provided in NCERT TextBook.

### NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.3

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.3 are part of Class 10 Maths NCERT Solutions. Here we have given NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3

 Board CBSE Textbook NCERT Class Class 10 Subject Maths Chapter Chapter 6 Chapter Name Triangles Exercise Ex 6.3 Number of Questions Solved 16 Category NCERT Solutions

### NCERT Solutions For Class 10 Maths Chapter 6 Ex 6.3

Ex 6.3 Class 10 Maths Question 1.
State which pairs of triangles in the given figures are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form :  Solution:  Ex 6.3 Class 10 Maths Question 2.
In the given figure, ∆ODC ~ ∆OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB. Solution: Ex 6.3 Class 10 Maths Question 3.
Diagonals AC and BD of a trape∠ium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that OAOC=OBOD
Solution: Ex 6.3 Class 10 Maths Question 4.
In the given figure, QRQS=QTPR and ∠1 = ∠2. show that ∆PQR ~ ∆TQR. Solution: Ex 6.3 Class 10 Maths Question 5.
S and T are points on sides PR and QR of ∆PQR such that ∠P = ∠RTS. Show that ∆RPQ ~ ∆RTS.
Solution: Ex 6.3 Class 10 Maths Question 6.
In the given figure, if ∆ABE ≅ ∆ACD, show that ∆ADE ~ ∆ABC. Solution: Ex 6.3 Class 10 Maths Question 7.
In the given figure, altitudes AD and CE of ∆ABC intersect each other at the point P. Show that:
(i) ∆AEP ~ ∆CDP
(ii) ∆ABD ~ ∆CBE
(iv) ∆PDC ~ ∆BEC Solution: Ex 6.3 Class 10 Maths Question 8.
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ∆ABE ~ ∆CFB.
Solution: Ex 6.3 Class 10 Maths Question 9.
In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: Solution: Ex 6.3 Class 10 Maths Question 10.
CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ∆ABC and ∆EFG respectively. If ∆ABC ~ ∆FEG, show that Solution:  Ex 6.3 Class 10 Maths Question 11.
In the given figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that ∆ABD ~ ∆ECF. Solution: Ex 6.3 Class 10 Maths Question 12.
Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of ∆PQR (see in given figure). Show that ∆ABC ~ ∆bPQR. Solution: Ex 6.3 Class 10 Maths Question 13.
D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD.
Solution: Ex 6.3 Class 10 Maths Question 14.
Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that ∆ABC ~ ∆PQR.
Solution: Ex 6.3 Class 10 Maths Question 15.
A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
Solution: Ex 6.3 Class 10 Maths Question 16.
If AD and PM are medians of triangles ABC and PQR respectively, where
∆ABC ~ ∆PQR. Prove that ABPQ=ADPM
Solution: ### NCERT Solutions For Class 10 Maths Chapter 6 Triangles Exercise wise links below :

CBSE NCERT Solutions of Chapter 1

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